A ball is thrown up with a certain velocity, it attains 50 m and come back to the thrower then the

Question

Accepted Answer

To analyze the question, we need to understand the concepts of distance and displacement in the context of the motion of the ball.

1. **Total Distance Covered**: This refers to the total path length traveled by the ball during its motion. When the ball is thrown upwards, it travels up to a height of 50 m and then comes back down to the thrower's hand. Therefore, the total distance covered by the ball is the distance going up (50 m) plus the distance coming back down (50 m). This results in a total distance of:
   $$
   \text{Total Distance} = 50 \, \text{m (up)} + 50 \, \text{m (down)} = 100 \, \text{m}
   $$

2. **Total Displacement**: Displacement is defined as the change in position of an object. It is a vector quantity that considers only the initial and final positions, not the path taken. In this case, the ball is thrown up and then comes back to the same position from where it was thrown. Thus, the initial and final positions are the same, leading to a displacement of:
   $$
   \text{Total Displacement} = \text{Final Position} - \text{Initial Position} = 0 \, \text{m}
   $$

Now, let's evaluate the options:

1. **Total distance covered by it is 50 m**: This option is incorrect because the total distance covered is 100 m, not 50 m.

2. **Total displacement covered by it is 100 m**: This option is incorrect because the total displacement is 0 m, as explained above.

3. **Total displacement is zero**: This option is correct because the ball returns to the same position from which it was thrown, resulting in zero displacement.

4. **Total distance covered by it is 120 m**: This option is incorrect because the total distance covered is 100 m, not 120 m.

Based on this analysis, the correct answer is:

**3. Total displacement is zero**.