Question
Easy
The area of a trapezium is 105 cm² and its height is 7 cm. If one of the parallel sides is longer than the other by 6 cm, then the length of the longer side, in cm, is
1
18
2
16
3
15
4
12
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: CTET_P2
Chapter: 2D Geometry
Topic: Trapeziums
Correct Answer
Option A
Explanation
To solve the problem of finding the length of the longer side of the trapezium, we start by using the formula for the area of a trapezium: \[ \text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height} \] Given: - Area = 105 cm² - Height = 7 cm - One base is longer than the other by 6 cm Let the length of the shorter base be \( x…Read More
Similar Questions from REET Exam - Paper 1 - Year 2018
Question 1
Easy
Source :
2D Geometry
BD is the diagonal of parallelogram ABCD such that ∠CBD=12x, ∠ABD=7y, ∠ADB=60° and ∠CDB=28°. Then, the value of 2x+3y is :
Chapter :
2D Geometry
Topic :
Parallelograms
Question 2
Easy
Source :
2D Geometry
PQRS is a parallelogram whose diagonals PR and QS intersect at a point O such that OP = (x + 7) cm, OQ= (x +…
Chapter :
2D Geometry
Topic :
Parallelograms
Question 3
Easy
Source :
2D Geometry
In trapezium PQRS, PQ || SR and the ratio of PQ to SR is 3:2. If the area of the trapezium is 480 cm$^2$ and…
Chapter :
2D Geometry
Topic :
Trapeziums
Question 4
Easy
Source :
2D Geometry
The distance between the parallel sides AB and CD of a trapezium ABCD is 12 cm. If AB<CD, CD=24 cm and AD=BC=13 cm, then area…
Chapter :
2D Geometry
Topic :
Trapeziums