Question
Easy

Consider the Boolean function $f=(a+bc).(pq+r)$ Complement $f'$ of function f is :

1
$(a'+b'c').(p'q'+r')$
2
$a'(b'+c')+(p'+q')r'$
3
$(a'+b'c')+(p'q'+r')$
4
$(a'b'c')+(p'q'r')$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter:
Topic:
Correct Answer
Option B
Explanation

The correct option is (2): The function $f=(a+bc).(pq+r)$ is a conjunction (AND operation) of two large terms: $A=(a+bc)$ and $B=(pq+r)$. To find the complement $f'$, we must apply De Morgan's laws. De Morgan's Second Law, which states that the complement of a product is the sum of the complements ($\\overline{A \\cdot B} = \\overline{A} + \\overline{B}$), is applied first. This gives $f' = \\overline{(a+bc)} + \\overline{(pq+r)}$. Next, we apply De…Read More

Consider the boolean function - HTET Level 3 | Clear Cutoff