Question
Easy
How many natural numbers between 1 and 500 are divisible by each of the numbers 3, 5 and 7?
1
3
2
4
3
5
4
6
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: CTET_P2
Chapter: Number Operations
Topic: LCM & HCF
Correct Answer
Option B
Explanation
To determine how many natural numbers between 1 and 500 are divisible by each of the numbers 3, 5, and 7, we need to find the numbers that are divisible by the least common multiple (LCM) of these three numbers. 1. Calculate the LCM of 3, 5, and 7: - The prime factorization of 3 is \(3^1\). - The prime factorization of 5 is \(5^1\). - The prime factorization of…Read More
Similar Questions from REET Exam - Paper 1 - Year 2018
Question 1
Easy
Source :
Number Operations
The smallest four-digit number which is a multiple of 6, 7 and 4 is :
Chapter :
Number Operations
Topic :
LCM & HCF
Question 2
Easy
Source :
Number Operations
A frog jumps 3 steps and a rabbit jumps 7 steps at a time starting from a place O. At which of the following steps,…
Chapter :
Number Operations
Topic :
LCM & HCF
Question 3
Easy
Source :
Number Operations
The ratio of two numbers is 3 : 7 and their LCM is 630. Then, sum of the LCM and HCF of these numbers is…
Chapter :
Number Operations
Topic :
LCM & HCF
Question 4
Easy
Source :
Number Operations
If 21168 = 2$^a$ × 3$^b$ × 7$^c$, where a, b and care natural numbers, then what is the value of (4a – 5b +…
Chapter :
Number Operations
Topic :
Prime Factorization