Question
Easy
If (2x+5y)$^2$−5(2x+5y) – 14 = (2x+5y+p)(2x + 5y +q), then the value of (p+q) is :
1
7
2
-14
3
9
4
-5
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: CTET_P2
Chapter: Algebra
Topic: Factors
Correct Answer
Option D
Explanation
To solve the given equation \((2x+5y)^2 - 5(2x+5y) - 14 = (2x+5y+p)(2x+5y+q)\) and determine the value of \(p+q\), we need to factor the quadratic expression on the left-hand side and compare it with the right-hand side. ### Step-by-Step Explanation: 1. Expand the Left-Hand Side: \[ (2x+5y)^2 - 5(2x+5y) - 14 \] Let \(z = 2x + 5y\). Then the expression becomes: \[ z^2 - 5z - 14 \] 2. **Factor…Read More
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