Question
Easy
If a, b, c are three unequal numbers such that a, b, c are in arithmetic progression and $b-a$, $c-b$, a are in geometric progression, then $a:b:c$ is:
1
1:02:04
2
1:03:05
3
1:02:03
4
2:03:04
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Arithmetic, Algebra and Trigonometry
Topic: Arithmetic Progression
Correct Answer
Option C
Explanation
To solve the problem, we need to analyze the conditions given for the numbers \(a\), \(b\), and \(c\). 1. Arithmetic Progression Condition: The numbers \(a\), \(b\), and \(c\) are in arithmetic progression. This means: \[ b = a + d \quad \text{and} \quad c = a + 2d \] where \(d\) is the common difference. 2. Geometric Progression Condition: The numbers \(b-a\), \(c-b\), and \(a\) are in geometric progression. This…Read More
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