Question
Easy
If $\int\frac{log_{e}x}{(1+log_{e}x)^{2}}dx=\frac{f(x)}{(1+log_{e}x)}+c,$ then $f(x)=$
1
x
2
-x
3
$x^{2}$
4
$-x^{2}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Calculus
Topic: Integration
Correct Answer
Option A
Explanation
To solve the given integral and determine why Option 1 is correct, we need to evaluate the integral \(\int \frac{\log_e x}{(1 + \log_e x)^2} \, dx\) and compare it to the expression \(\frac{f(x)}{(1 + \log_e x)} + c\). ### Explanation: 1. Substitution Method: - Let \( u = \log_e x \). Then, \( du = \frac{1}{x} \, dx \) or \( dx = x \, du \). - Since \(…Read More
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