Question
Easy

In a quadrilateral ABCD, ∠A + ∠C = 2(∠B + ∠D). If ∠A = 140° and ∠D = 60°, then ∠B =

1
$60^{\circ}$
2
$80^{\circ}$
3
$90^{\circ}$
4
$120^{\circ}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: 2D Geometry
Topic: Quadrilaterals
Correct Answer
Option A
Explanation

To solve the problem, we need to determine the value of ∠B in the quadrilateral ABCD, given that ∠A + ∠C = 2(∠B + ∠D) and the values of ∠A and ∠D are 140° and 60°, respectively. Let's break down the problem step by step: 1. Given Information: - ∠A = 140° - ∠D = 60° - ∠A + ∠C = 2(∠B + ∠D) 2. Substitute the Known Values: -…Read More

In a quadrilateral abcd - HTET Level 2 | Clear Cutoff