Question
Easy
$\int_{0}^{\pi}\frac{x}{a^{2}cos^{2}x+b^{2}sin^{2}x}dx$ is equal to:
1
$\frac{\pi^{2}}{ab}$
2
$\frac{\pi^{2}}{2ab}$
3
$\frac{\pi^{2}}{4ab}$
4
$\frac{\pi^{2}}{9ab}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Calculus
Topic: Integration
Correct Answer
Option B
Explanation
To solve the integral \(\int_{0}^{\pi}\frac{x}{a^{2}\cos^{2}x+b^{2}\sin^{2}x}dx\), we need to evaluate it using appropriate techniques and verify why Option 2, \(\frac{\pi^{2}}{2ab}\), is the correct answer. ### Explanation for Option 2: 1. Symmetry and Substitution: The integral has limits from 0 to \(\pi\), which suggests that symmetry might play a role. Consider the substitution \(x = \pi - t\), which transforms the integral as follows: \[ \int_{0}^{\pi} \frac{x}{a^{2}\cos^{2}x + b^{2}\sin^{2}x} \, dx =…Read More
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