Question
Easy

Let $A_{n}=\int_{0}^{\frac{\pi}{4}}tan^{n}x~dx,$ then $A_{10}+A_{8}=$

1
$\frac{1}{8}$
2
$\frac{1}{9}$
3
$\frac{1}{11}$
4
$\frac{1}{13}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Calculus
Topic: Integration
Correct Answer
Option B
Explanation

To solve the problem, we need to evaluate the integrals \( A_{10} = \int_{0}^{\frac{\pi}{4}} \tan^{10} x \, dx \) and \( A_{8} = \int_{0}^{\frac{\pi}{4}} \tan^{8} x \, dx \), and then find their sum \( A_{10} + A_{8} \). ### Explanation: The integral \( A_n = \int_{0}^{\frac{\pi}{4}} \tan^n x \, dx \) can be evaluated using a reduction formula. The reduction formula for the integral of powers of tangent is…Read More