Question
Easy
P is a point on line AB and PQ is a ray such that ∠ QPA = 7x and ∠ QPB = 5x. Then, the value of (8x – 10°) is :
1
118°
2
110°
3
140°
4
102°
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: CTET_P2
Chapter: 2D Geometry
Topic: Lines & Angles
Correct Answer
Option B
Explanation
To solve the problem, we need to determine the value of \(8x - 10^\circ\) given the angles \(\angle QPA = 7x\) and \(\angle QPB = 5x\). ### Explanation: 1. Understanding the Geometry: - Since \(P\) is a point on line \(AB\) and \(PQ\) is a ray, the angles \(\angle QPA\) and \(\angle QPB\) are formed on a straight line. - The sum of angles on a straight line is \(180^\circ\).…Read More
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