Raju has turpentine oil in 5 containers each of 20 L size. He fills them in 10 cans of 5 L, 10 cans of 2 L and rest in 1 L cans. Number of 1 L cans filled is :

Question

Accepted Answer

Raju has a total of 5 containers, each with a capacity of 20 liters. Therefore, the total volume of turpentine oil is:

$$ 5 \text{ containers} \times 20 \text{ L/container} = 100 \text{ L} $$

Raju fills this oil into cans of different sizes: 5 L, 2 L, and 1 L. Let's calculate how much oil is used in the 5 L and 2 L cans first:

1. **5 L Cans:**
   - Number of 5 L cans = 10
   - Total volume in 5 L cans = $ 10 \text{ cans} \times 5 \text{ L/can} = 50 \text{ L} $

2. **2 L Cans:**
   - Number of 2 L cans = 10
   - Total volume in 2 L cans = $ 10 \text{ cans} \times 2 \text{ L/can} = 20 \text{ L} $

Now, let's calculate the total volume of oil used in the 5 L and 2 L cans:

$$ 50 \text{ L} + 20 \text{ L} = 70 \text{ L} $$

The remaining oil to be filled in 1 L cans is:

$$ 100 \text{ L} - 70 \text{ L} = 30 \text{ L} $$

Since each 1 L can holds 1 liter, the number of 1 L cans needed is:

$$ 30 \text{ L} \div 1 \text{ L/can} = 30 \text{ cans} $$

Therefore, the number of 1 L cans filled is 30, which corresponds to Option 2.

**Explanation for Incorrect Options:**

- **Option 1 (25):** This option is incorrect because it suggests fewer 1 L cans than needed to hold the remaining 30 liters of oil.
  
- **Option 3 (22):** This option is incorrect because it also suggests fewer 1 L cans than required for the 30 liters of remaining oil.
  
- **Option 4 (28):** This option is incorrect because it suggests fewer 1 L cans than necessary to accommodate the 30 liters of oil left after filling the 5 L and 2 L cans.

Thus, the correct answer is indeed Option 2, which is 30.