Question
Easy
Ram measures the period of oscillation of a simple pendulum. In successive measurements, the reading are 2.63 s, 2.56 s, 2.42 s, 2.71 s and 2.80 s. The mean absolute error and percentage error are respectively:
1
0.11 s and 4%
2
0.068 s and 4%
3
0.068 s and 2.6%
4
0.11 s and 2.6%
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Motion
Topic: Describing Motion
Correct Answer
Option A
Explanation
To determine why Option 1 is the correct answer, we need to calculate the mean absolute error and the percentage error based on the given measurements of the pendulum's oscillation period. 1. Calculate the Mean Period: The given measurements are 2.63 s, 2.56 s, 2.42 s, 2.71 s, and 2.80 s. The mean period \( T \) is calculated as follows: \[ T = \frac{2.63 + 2.56 + 2.42 +…Read More
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