Question
Easy
Solve $4x+3<6x+7$
1
(-2,$\infty$)
2
(-2, +2)
3
(-2, 0)
4
(2,$\infty$)
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter:
Topic:
Correct Answer
Option A
Explanation
To solve the inequality \(4x + 3 < 6x + 7\), we need to isolate \(x\) on one side of the inequality. Let's go through the steps: 1. Subtract \(4x\) from both sides: \[ 4x + 3 - 4x < 6x + 7 - 4x \] This simplifies to: \[ 3 < 2x + 7 \] 2. Subtract 7 from both sides: \[ 3 - 7 < 2x + 7…Read More
Similar Questions from HTET Exam - Level 3 - Year 2016
Question 1
Easy
Source :
HTET 2016
For all real values of x, the minimum value of $\frac{1-x+x^{2}}{1+x+x^{2}}$ is
Question 2
Easy
Source :
HTET 2016
If $\vec{a}\times\vec{b}=\vec{c}\times\vec{d}$ and $\vec{a}\times\vec{c}=\vec{b}\times\vec{d}$, then vectors $\vec{a}-\vec{d}$ and $\vec{b}-\vec{c}$ are
Question 3
Easy
Source :
HTET 2016
If p is a real number such that $0<p<1$ and x and y are real numbers with x < y, then
Question 4
Easy
Source :
HTET 2016
$cos~2x=$