Question
Easy
The number of diagonals of a polygon of n sides is equal to:
1
$\frac{n(n-3)}{2}$
2
$\frac{n(n-1)}{2}$
3
$\frac{n(n-2)}{2}$
4
$\frac{n}{2}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Vectors and Coordinate Geometry
Topic: Two Dimensional Geometry
Correct Answer
Option A
Explanation
To determine the number of diagonals in a polygon with \( n \) sides, we use the formula \(\frac{n(n-3)}{2}\). Let's break down why this formula is correct and why the other options are incorrect. ### Explanation for Option 1: \(\frac{n(n-3)}{2}\) 1. Understanding Diagonals: A diagonal is a line segment connecting two non-adjacent vertices in a polygon. In a polygon with \( n \) sides, each vertex can connect to \(…Read More
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