Question
Easy
The radii of curvature at the origin for the curve $x^{3}+y^{3}=3axy$ are each equal to:
1
$\frac{a}{2}$
2
$\frac{a}{3}$
3
$\frac{2a}{3}$
4
$\frac{3a}{2}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Vectors and Coordinate Geometry
Topic: Two Dimensional Geometry
Correct Answer
Option D
Explanation
To determine the radii of curvature at the origin for the curve given by the equation \(x^3 + y^3 = 3axy\), we need to analyze the curvature of the curve at the origin \((0, 0)\). ### Step-by-Step Explanation: 1. Implicit Differentiation: The given equation is \(x^3 + y^3 = 3axy\). We differentiate both sides with respect to \(x\) to find the slope of the tangent (i.e., \(\frac{dy}{dx}\)). \[ 3x^2 +…Read More
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