Question
Easy
The sum of all interior angles of n-sided polygon is:
1
(2n−4)×90
2
(2n+4)×90
3
(n−2)×90
4
(n+2)×90
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Indian Art History
Topic: Medieval Indian Art
Correct Answer
Option A
Explanation
The correct option is 1: The standard formula for calculating the sum of all interior angles of an $n$-sided polygon is derived from the fact that any $n$-sided polygon can be divided into $n-2$ non-overlapping triangles by drawing diagonals from a single vertex. Since the sum of the interior angles of one triangle is $180^\\circ$, the total sum is expressed as $(n-2) \\times 180^\\circ$. To see why option 1, $(2n-4)…Read More
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