When lead nitrate is heated in glass tube: (i) A double decomposition reaction takes place. (ii) Brown fumes of $NO_{2}$ are evolved. (iii) White residue is left behind in the glass tube. Out of (i), (ii) and (iii) which statement(s) is/are correct?
When lead nitrate is heated, it undergoes thermal decomposition rather than a double decomposition reaction. This is a key distinction that helps us understand why Option 3 is the correct answer. 1. Explanation for Option 3 (Correct Answer): - When lead nitrate (\(Pb(NO_3)_2\)) is heated, it decomposes to form lead oxide (\(PbO\)), nitrogen dioxide (\(NO_2\)), and oxygen (\(O_2\)). The reaction is as follows: \[ 2Pb(NO_3)_2 \rightarrow 2PbO + 4NO_2 +…Read More
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