Question
Easy
A ball thrown up is caught by the thrower 6 sec after start. The height to which the ball has risen is : (g = 10 m/s^2)
1
30 m
2
45 m
3
60 m
4
90 m
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Motion
Topic: Describing Motion
Correct Answer
Option B
Explanation
To determine the height to which the ball has risen, we need to analyze the motion of the ball using the principles of physics, specifically the equations of motion under uniform acceleration due to gravity. 1. Understanding the Motion: - The ball is thrown upwards and caught by the thrower after 6 seconds. This means the total time for the upward and downward journey is 6 seconds. - Since the…Read More
Similar Questions from REET Exam - Paper 1 - Year 2018
Question 1
Easy
Source :
HTET 2022
Which of the following equation does not represent a simple harmonic motion ?
Chapter :
Motion
Topic :
Describing Motion
Question 2
Easy
Source :
HTET 2022
A torque of 50 Nm acting on a wheel at rest rotate it through 200 radians in 5 seconds. The angular acceleration (in rad/sec$^2)$ will…
Chapter :
Motion
Topic :
Describing Motion
Question 3
Easy
Source :
HTET 2022
If a body loses half of its velocity on penetrating 3 cm in a wooden block, then how much will it penetrate more before coming…
Chapter :
Motion
Topic :
Describing Motion
Question 4
Easy
Source :
HTET 2023
If an object is moving with constant acceleration along one direction only, then the distance travelled in the nth second is : [Take U =…
Chapter :
Motion
Topic :
Describing Motion