Question
Easy

A uniform ring of mass 'm' is lying at a distance $\sqrt{3}R$ from the center of the sphere of mass 'M' just over the sphere (where 'R' is the radius of the ring as well as of the sphere), then the magnitude of the gravitational force between them is:

1
$\frac{\sqrt{3}GMm}{R^{2}}$
2
$\frac{\sqrt{3}}{8}\frac{GMm}{R^{2}}$
3
$\frac{GMm}{8R^{2}}$
4
$\frac{G}{2}\frac{Mm}{R^{2}}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Gravitation
Topic: Mass and Weight
Correct Answer
Option B
Explanation

To determine the gravitational force between a uniform ring and a sphere, we need to consider the gravitational interaction between the two objects. The given problem specifies that the ring is at a distance of \(\sqrt{3}R\) from the center of the sphere, where \(R\) is the radius of both the ring and the sphere. ### Explanation for Option 2: The gravitational force between two masses is given by Newton's lawтАжRead More