Question
Easy
The expression (x - y) (x$^2$ + xy + y$^2$) + (x + y) (x$^2$ тАУ xy + y$^2$) тАУ (x + y) (x$^2$ тАУ y$^2$) is equal to
1
x$^3$ тАУ y$^3$ + xy(x + y)
2
y$^3$ - x$^3$ + xy(y + x)
3
x$^3$ + y$^3$ + xy(y тАУ x)
4
x$^3$ + y$^3$ +xy(x - y)
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: CTET_P2
Chapter: Algebra
Topic: Algebraic Expressions
Correct Answer
Option C
Explanation
To determine why Option 3 is the correct answer for the given expression, let's simplify the expression step by step and verify that it matches the form given in Option 3. The expression is: \[ (x - y)(x^2 + xy + y^2) + (x + y)(x^2 - xy + y^2) - (x + y)(x^2 - y^2) \] 1. Simplify each part of the expression: - First Term: \((x - y)(x^2тАжRead More
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