Question
Easy

Find the value of: $\frac{(3^{-7} + 3^{-10}) \times 3^{-5}}{\left[ \left( \frac{-2}{3} \right)^{-2} \right]^2}$

1
$\frac{742}{16}$
2
$\frac{729}{16}$
3
$\frac{16}{729}$
4
$\frac{16}{829}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 1
Chapter: Power & Roots
Topic: Exponents & Powers
Correct Answer
Option C
Explanation

To solve the given expression and verify why Option 3 is the correct answer, we need to simplify the expression step by step. The expression is: \[ \frac{(3^{-7} + 3^{-10}) \times 3^{-5}}{\left[ \left( \frac{-2}{3} \right)^{-2} \right]^2} \] Step 1: Simplify the numerator The numerator is \((3^{-7} + 3^{-10}) \times 3^{-5}\). First, factor out the common term \(3^{-10}\) from the terms inside the parentheses: \[ 3^{-7} + 3^{-10} = 3^{-10} \timesтАжRead More