Question
Easy

Find the value of : $\sqrt[4]{81} + \sqrt[3]{216} + \sqrt[5]{32}$

1
10
2
11
3
12
4
32
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 1
Chapter: Power & Roots
Topic: Square Root & Cube Roots
Correct Answer
Option B
Explanation

To find the value of \(\sqrt[4]{81} + \sqrt[3]{216} + \sqrt[5]{32}\), we need to evaluate each term separately and then sum them up. 1. Evaluate \(\sqrt[4]{81}\): \[ \sqrt[4]{81} = \sqrt[4]{3^4} = 3 \] Since \(81 = 3^4\), the fourth root of 81 is 3. 2. Evaluate \(\sqrt[3]{216}\): \[ \sqrt[3]{216} = \sqrt[3]{6^3} = 6 \] Since \(216 = 6^3\), the cube root of 216 is 6. 3. Evaluate \(\sqrt[5]{32}\): \[ \sqrt[5]{32} =…Read More