Question
Easy
Find the value of m - n, if $\frac{9^n \times 3^2 \times \{(3)^{-n/3}\}^{-2} - (27)^n}{3^{3m} \times 2^3} = \frac{1}{27}$ :
1
-2
2
1
3
-1
4
2
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 1
Chapter: Power & Roots
Topic: Exponents & Powers
Correct Answer
Option B
Explanation
To solve the given problem and justify why Option 2 is correct, we need to simplify the expression and find the value of \( m - n \). The expression given is: \[ \frac{9^n \times 3^2 \times \{(3)^{-n/3}\}^{-2} - (27)^n}{3^{3m} \times 2^3} = \frac{1}{27} \] Let's simplify the expression step by step: 1. Simplify the numerator: - \( 9^n = (3^2)^n = 3^{2n} \) - \( (3)^{-n/3}^{-2} = 3^{2 \times…Read More
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