Question
Easy

$\frac{16 \times 2^{n+1} - 4 \times 2^n}{16 \times 2^{n+2} - 2 \times 2^{n+2}}$ =

1
1
2
$\frac{1}{2}$
3
$\frac{1}{4}$
4
$\frac{1}{2^n}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Power & Roots
Topic: Exponents & Powers
Correct Answer
Option B
Explanation

To solve the given expression and verify why Option 2 is the correct answer, let's simplify the expression step by step: The expression is: \[ \frac{16 \times 2^{n+1} - 4 \times 2^n}{16 \times 2^{n+2} - 2 \times 2^{n+2}} \] Step 1: Simplify the numerator The numerator is \(16 \times 2^{n+1} - 4 \times 2^n\). - Rewrite \(16 \times 2^{n+1}\) as \(16 \times 2 \times 2^n = 32 \times 2^n\). -тАжRead More