Question
Easy

H.C.F. of $\frac{4}{5}$ and $\frac{7}{15}$ is

1
$\frac{1}{15}$
2
$\frac{28}{75}$
3
$\frac{1}{25}$
4
$\frac{1}{5}$
Question Details
Time to Solve: 12
Exam: HPTGT
Level/Paper: HPTGT NONMED
Chapter:
Topic:
Correct Answer
Option A
Explanation

The correct option is 1: To find the H.C.F. (Highest Common Factor) of fractions, we use the following formula: $$H.C.F. \\text{ of fractions} = \\frac{H.C.F. \\text{ of numerators}}{L.C.M. \\text{ of denominators}}$$ Given fractions are $\frac{4}{5}$ and $\frac{7}{15}$. Step 1: Find the H.C.F. of the numerators. The numerators are 4 and 7. Prime factorization of 4: $2 \\times 2$ Prime factorization of 7: $7$ The only common factor is 1. So,…Read More

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