Question
Easy
If a circle passing through (1, 2) and intersects $x^{2}+y^{2}=4$ orthogonally, then the locus of the centre of the circle is:
1
$x^{2}+y^{2}-3x-8y+1=0$
2
$x^{2}+y^{2}-2x-6y-7=0$
3
$2x+4y-9=0$
4
$2x+4y-1=0$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Vectors and Coordinate Geometry
Topic: Two Dimensional Geometry
Correct Answer
Option C
Explanation
To determine the locus of the center of a circle that passes through the point (1, 2) and intersects the circle given by \(x^2 + y^2 = 4\) orthogonally, we need to use the concept of orthogonal circles. ### Explanation: 1. Orthogonal Circles Condition: Two circles are orthogonal if the sum of the products of their corresponding coefficients is zero. For a circle with center \((h, k)\) and radius \(r\),…Read More
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