Question
Easy
If coordinates of focus (±5, 0) & vertices (±13, 0), then equation of ellipse will be
1
$\frac{x^{2}}{169}-\frac{y^{2}}{144}=1$
2
$\frac{x^{2}}{144}+\frac{y^{2}}{169}=1$
3
$\frac{x^{2}}{144}-\frac{y^{2}}{169}=1$
4
$\frac{x^{2}}{169}+\frac{y^{2}}{144}=1$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter:
Topic:
Correct Answer
Option D
Explanation
The correct answer is Option 4: \(\frac{x^{2}}{169}+\frac{y^{2}}{144}=1\). ### Explanation: To determine the equation of the ellipse, we need to understand the properties of an ellipse and how its equation is derived from its geometric features. 1. Vertices and Foci: - The given vertices are \((\pm13, 0)\), which means the major axis is along the x-axis, and the length of the major axis is \(2a = 26\). Therefore, \(a = 13\).…Read More
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