Question
Easy
If x = $\frac{\sqrt{3} + 1}{\sqrt{3} - 1}$ and y = $\frac{\sqrt{3} - 1}{\sqrt{3} + 1}$, then the value of $(x^2+y^2)$ is :
1
14
2
12
3
13
4
16
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Power & Roots
Topic: Surds & Indices
Correct Answer
Option A
Explanation
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