Question
Easy

If $x=3-\sqrt{5}$, then $\frac{\sqrt{x}}{\sqrt{2}+\sqrt{3x-2}}=$

1
5
2
$\sqrt{5}$
3
$\frac{1}{5}$
4
$\frac{1}{\sqrt{5}}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Arithmetic, Algebra and Trigonometry
Topic: Real Number System
Correct Answer
Option D
Explanation

To solve the problem and justify why Option 4 is correct, we need to evaluate the expression \(\frac{\sqrt{x}}{\sqrt{2}+\sqrt{3x-2}}\) given that \(x = 3 - \sqrt{5}\). Step-by-step Explanation: 1. Substitute \(x\) into the expression: - We have \(x = 3 - \sqrt{5}\). - Therefore, \(\sqrt{x} = \sqrt{3 - \sqrt{5}}\). 2. Simplify the denominator: - Calculate \(3x - 2\): \[ 3x - 2 = 3(3 - \sqrt{5}) - 2 = 9 -тАжRead More

If x3sqrt5 then fracsqrtxsqrt2sqrt3x2 - HTET Level 3 | Clear Cutoff