Question
Easy

If ($x^4 + \frac{1}{x^4})$ = 119 and x > 1, then the value of ($x^3 - \frac{1}{x^3}$) is:

1
18
2
36
3
54
4
72
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Power & Roots
Topic: Exponents & Powers
Correct Answer
Option B
Explanation

To solve the problem and justify why Option 2 is correct, we need to find the value of \(x^3 - \frac{1}{x^3}\) given that \(x^4 + \frac{1}{x^4} = 119\). ### Step-by-step Explanation: 1. Given Equation: \[ x^4 + \frac{1}{x^4} = 119 \] 2. Relate to \(x^2 + \frac{1}{x^2}\): We know that: \[ \left(x^2 + \frac{1}{x^2}\right)^2 = x^4 + 2 + \frac{1}{x^4} \] Therefore: \[ x^4 + \frac{1}{x^4} = \left(x^2 + \frac{1}{x^2}\right)^2тАжRead More

If x4 frac1x4 - HTET Level 2 | Clear Cutoff