Question
Easy
In a pentagon ABCDE, тИаA = (2x + 9┬░), тИаB = (2x + 1┬░), тИаC = (2xтИТ1┬░), тИаD = (2x +5┬░) and тИаE = (2x-4┬░). Then, value of (2x + 10┬░) is :
1
124┬░
2
114┬░
3
116┬░
4
118┬░
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: CTET_P2
Chapter: 2D Geometry
Topic: Polygons
Correct Answer
Option C
Explanation
To solve the problem, we need to determine the value of \(2x + 10^\circ\) given the angles of a pentagon ABCDE. The angles are given as follows: - \(\angle A = (2x + 9^\circ)\) - \(\angle B = (2x + 1^\circ)\) - \(\angle C = (2x - 1^\circ)\) - \(\angle D = (2x + 5^\circ)\) - \(\angle E = (2x - 4^\circ)\) The sum of the interior angles of aтАжRead More
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