Question
Easy
In a quadrilateral ABCD, тИаA + тИаC = 2(тИаB + тИаD). If тИаA = 140┬░ and тИаD = 60┬░, then тИаB =
1
$60^{\circ}$
2
$80^{\circ}$
3
$90^{\circ}$
4
$120^{\circ}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: 2D Geometry
Topic: Quadrilaterals
Correct Answer
Option A
Explanation
To solve the problem, we need to determine the value of тИаB in the quadrilateral ABCD, given that тИаA + тИаC = 2(тИаB + тИаD) and the values of тИаA and тИаD are 140┬░ and 60┬░, respectively. Let's break down the problem step by step: 1. Given Information: - тИаA = 140┬░ - тИаD = 60┬░ - тИаA + тИаC = 2(тИаB + тИаD) 2. Substitute the Known Values: -тАжRead More
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