Question
Easy

In a quadrilateral ABCD, тИаA + тИаC = 2(тИаB + тИаD). If тИаA = 140┬░ and тИаD = 60┬░, then тИаB =

1
$60^{\circ}$
2
$80^{\circ}$
3
$90^{\circ}$
4
$120^{\circ}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: 2D Geometry
Topic: Quadrilaterals
Correct Answer
Option A
Explanation

To solve the problem, we need to determine the value of тИаB in the quadrilateral ABCD, given that тИаA + тИаC = 2(тИаB + тИаD) and the values of тИаA and тИаD are 140┬░ and 60┬░, respectively. Let's break down the problem step by step: 1. Given Information: - тИаA = 140┬░ - тИаD = 60┬░ - тИаA + тИаC = 2(тИаB + тИаD) 2. Substitute the Known Values: -тАжRead More

In a quadrilateral abcd - HTET Level 2 | Clear Cutoff