In an examination, A gets 10% more marks than B and B gets 15% more marks than C. How much percent more does A get than C ?

Question

Accepted Answer

To determine how much percent more marks A gets than C, we need to follow the given relationships between their marks.

1. **Understanding the Relationships:**
   - A gets 10% more marks than B.
   - B gets 15% more marks than C.

2. **Calculating the Marks:**
   - Let's assume C's marks are 100 units.
   - Since B gets 15% more marks than C, B's marks = 100 + 15% of 100 = 100 + 15 = 115 units.
   - A gets 10% more marks than B, so A's marks = 115 + 10% of 115 = 115 + 11.5 = 126.5 units.

3. **Calculating the Percentage Increase from C to A:**
   - The difference in marks between A and C = 126.5 - 100 = 26.5 units.
   - The percentage increase from C to A = (Difference / C's marks) * 100 = (26.5 / 100) * 100 = 26.5%.

4. **Conclusion:**
   - A gets 26.5% more marks than C, which corresponds to Option 2: $26\frac{1}{2}\%$.

5. **Explanation of Incorrect Options:**
   - **Option 1 (0.25%):** This is incorrect because the calculated percentage increase from C to A is significantly larger than 0.25%.
   - **Option 3 (28$\frac{1}{2}\%$):** This is incorrect because the calculated percentage increase is 26.5%, not 28.5%.
   - **Option 4 (28$\frac{3}{4}\%$):** This is incorrect because the calculated percentage increase is 26.5%, not 28.75%.

Thus, the correct answer is Option 2: $26\frac{1}{2}\%$.