Question
Easy
$\int\frac{1}{cos^{3}x\sqrt{sin~2x}}dx$ is equal to:
1
$\sqrt{2}(\sqrt{cot~x}+\frac{1}{5}tan^{5/2}x)+c$
2
$\sqrt{2}(\sqrt{tan~x}+\frac{1}{5}tan^{5/2}x)+c$
3
$\sqrt{2}(\sqrt{tan~x}-\frac{1}{5}tan^{5/2}x)+c$
4
$\sqrt{2}(\sqrt{tan~x}+\frac{1}{5}tan~x)+c$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Calculus
Topic: Integration
Correct Answer
Option B
Explanation
To solve the integral \(\int\frac{1}{\cos^{3}x\sqrt{\sin 2x}}dx\), we need to simplify and manipulate the expression to match the form given in Option 2. Let's break down the process: 1. Simplification and Substitution: - We start with the integral \(\int\frac{1}{\cos^{3}x\sqrt{\sin 2x}}dx\). - Recall that \(\sin 2x = 2\sin x \cos x\). Therefore, \(\sqrt{\sin 2x} = \sqrt{2\sin x \cos x}\). - Substitute \(\sin x = t\), which implies \(dx = \frac{1}{\cos x} dt\)…Read More
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