Question
Easy

$\int\frac{1}{(x+5)^{7/8}(x-3)^{9/8}}dx$ is equal to:

1
$(\frac{x+5}{x-3})^{1/8}+c$
2
$(\frac{x+4}{x-4})^{1/8}+c$
3
$-(\frac{x+5}{x-3})^{1/8}+c$
4
$-(\frac{x+4}{x-4})^{1/8}+c$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Calculus
Topic: Integration
Correct Answer
Option C
Explanation

To solve the integral \(\int\frac{1}{(x+5)^{7/8}(x-3)^{9/8}}dx\), we need to find a function whose derivative matches the integrand. The correct answer is given as Option 3: \(-\left(\frac{x+5}{x-3}\right)^{1/8} + c\). ### Explanation for Option 3: 1. Substitution Method: - Consider the substitution \( u = \left(\frac{x+5}{x-3}\right)^{1/8} \). This implies that \( u^8 = \frac{x+5}{x-3} \). - Differentiating both sides with respect to \( x \), we get: \[ 8u^7 \cdot \frac{d}{dx}\left(\frac{x+5}{x-3}\right) = \frac{d}{dx}(u^8)…Read More

Intfrac1x578x398dx is equal to - HTET Level 3 | Clear Cutoff