Question
Easy
$\text{Square root of } (14 - 6\sqrt{5}) \text{ is :}$
1
$\pm (3 + \sqrt{5})$
2
$\pm (3 - \sqrt{5})$
3
$\pm (\sqrt{3} - 3)$
4
$\pm (\sqrt{3} + 3)$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Power & Roots
Topic: Square Root & Cube Roots
Correct Answer
Option B
Explanation
To determine the square root of \(14 - 6\sqrt{5}\), we need to find a number that, when squared, equals \(14 - 6\sqrt{5}\). The correct answer is given as Option 2: \(\pm (3 - \sqrt{5})\). Let's verify this and explain why this is the correct choice. ### Verification of Option 2: \(\pm (3 - \sqrt{5})\) 1. Calculate the square of \((3 - \sqrt{5})\): \[ (3 - \sqrt{5})^2 = 3^2 - 2тАжRead More
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