Question
Easy

The differential equation of all circles passing through the origin and having their centres on the x-axis is :

1
$x^{2}=y^{2}+xy\frac{dy}{dx}$
2
$x^{2}=y^{2}+3xy\frac{dy}{dx}$
3
$y^{2}=x^{2}+2xy\frac{dy}{dx}$
4
$y^{2}=x^{2}-2xy\frac{dy}{dx}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Vectors and Coordinate Geometry
Topic: Two Dimensional Geometry
Correct Answer
Option C
Explanation

To determine the differential equation of all circles passing through the origin and having their centers on the x-axis, we start by considering the general equation of a circle with center at \((a, 0)\) and radius \(r\): \[ (x - a)^2 + y^2 = r^2 \] Since the circle passes through the origin \((0, 0)\), substituting these coordinates into the equation gives: \[ a^2 + 0^2 = r^2 \implies r^2…Read More