Question
Easy
The equation of the tangent to the curve $x^{2}-y^{2}-8x+2y+11=0$ at (2, 1) is:
1
$x+2=0$
2
$2x+1=0$
3
$x-2y=0$
4
$x-2=0$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Vectors and Coordinate Geometry
Topic: Two Dimensional Geometry
Correct Answer
Option D
Explanation
To determine the equation of the tangent to the curve \(x^2 - y^2 - 8x + 2y + 11 = 0\) at the point (2, 1), we need to follow these steps: 1. Find the derivative of the curve: The given curve is implicitly defined, so we use implicit differentiation to find \(\frac{dy}{dx}\). Start with the equation: \[ x^2 - y^2 - 8x + 2y + 11 = 0 \]…Read More
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