Question
Easy

The length of perpendicular from (1, 2, 3) to the line $\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}$ is equal to:

1
3
2
5
3
7
4
$\sqrt{66}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Vectors and Coordinate Geometry
Topic: Three Dimensional Geometry
Correct Answer
Option C
Explanation

To determine the length of the perpendicular from the point \( (1, 2, 3) \) to the line given by the parametric equations \(\frac{x-6}{3} = \frac{y-7}{2} = \frac{z-7}{-2}\), we can use the formula for the distance from a point to a line in three-dimensional space. The line can be represented in vector form as: \[ \mathbf{r} = \mathbf{a} + t\mathbf{b} \] where \(\mathbf{a} = (6, 7, 7)\) is a point…Read More