Question
Easy

The probability that 'A' hits a target is 4/5 and 'B' hits the same target is 3/4. If each of them hits once. The probability that target hit only one of them is :

1
$\frac{3}{5}$
2
$\frac{6}{7}$
3
$\frac{7}{8}$
4
$\frac{7}{20}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Data Handling
Topic: Probability
Correct Answer
Option D
Explanation

To determine the probability that the target is hit by only one of them, we need to consider two scenarios: either 'A' hits the target and 'B' misses, or 'B' hits the target and 'A' misses. 1. Probability that 'A' hits and 'B' misses: - Probability that 'A' hits the target = \( \frac{4}{5} \) - Probability that 'B' misses the target = \( 1 - \frac{3}{4} = \frac{1}{4} \)…Read More