Question
Easy
The radius of curvature of the curve $p = b sin\psi cos\psi$ is:
1
p
2
2p
3
-3p
4
$\frac{3}{2}p$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Calculus
Topic: Integration
Correct Answer
Option C
Explanation
To determine the radius of curvature of the curve given by \( p = b \sin \psi \cos \psi \), we need to analyze the mathematical properties of the curve and apply the appropriate formulas for curvature. ### Explanation for Option 3: \(-3p\) 1. Understanding the Curve: The equation \( p = b \sin \psi \cos \psi \) can be rewritten using the trigonometric identity \( \sin 2\psi = 2…Read More
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