Question
Easy
The ratio of the coefficient of $x^{15}$ to the term independent of x in the expansion of $(x^{2}+\frac{2}{x})^{15}$ is:
1
12:32
2
1:32
3
32:12:00
4
32:1
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Algebra
Topic: Binomial Theorem
Correct Answer
Option B
Explanation
To solve the problem, we need to find the ratio of the coefficient of \(x^{15}\) to the term independent of \(x\) in the expansion of \((x^2 + \frac{2}{x})^{15}\). ### Step-by-step Explanation: 1. General Term in the Expansion: The general term in the expansion of \((x^2 + \frac{2}{x})^{15}\) is given by: \[ T_k = \binom{15}{k} (x^2)^{15-k} \left(\frac{2}{x}\right)^k = \binom{15}{k} x^{2(15-k)} \cdot \frac{2^k}{x^k} \] Simplifying, we get: \[ T_k = \binom{15}{k} \cdot…Read More
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