Question
Easy
The value of $\left(\frac{1}{2}\right)^{-2} \times \left(\frac{1}{3}\right)^{-2} \times \left(\frac{1}{4}\right)^{-2}$ is
1
-576
2
576
3
144
4
288
Question Details
Time to Solve: 12
Exam: REET
Level/Paper: Paper 2
Chapter:
Topic:
Correct Answer
Option B
Explanation
To solve the problem and verify why Option 2 is the correct answer, we need to evaluate the expression \(\left(\frac{1}{2}\right)^{-2} \times \left(\frac{1}{3}\right)^{-2} \times \left(\frac{1}{4}\right)^{-2}\). ### Step-by-step Explanation: 1. Understanding Negative Exponents: - A negative exponent indicates the reciprocal of the base raised to the positive of that exponent. Therefore, \(\left(\frac{1}{a}\right)^{-b} = a^b\). 2. Applying the Rule to Each Term: - \(\left(\frac{1}{2}\right)^{-2} = 2^2 = 4\) - \(\left(\frac{1}{3}\right)^{-2} = 3^2 =…Read More
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