Question
Easy
Value of $40^{\circ}20^{\prime}$ in Radian is
1
$\frac{121\pi}{540}$
2
$\frac{540\pi}{121}$
3
$\frac{121}{540\pi}$
4
$\frac{540}{121\pi}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter:
Topic:
Correct Answer
Option A
Explanation
To convert an angle from degrees to radians, we use the conversion factor \(\frac{\pi}{180}\). The given angle is \(40^{\circ}20^{\prime}\), which can be expressed in decimal degrees as \(40 + \frac{20}{60} = 40.3333\) degrees. Now, let's convert this angle to radians: \[ 40.3333 \times \frac{\pi}{180} = \frac{40.3333 \times \pi}{180} \] To simplify this, we multiply: \[ 40.3333 \times \pi \approx 126.9999\pi \] Now, we simplify the fraction: \[ \frac{126.9999\pi}{180} \approx \frac{121\pi}{540}…Read More
Similar Questions from HTET Exam - Level 3 - Year 2016
Question 1
Easy
Source :
HTET 2016
In a triangle ABC: $a~sin(B-C)+b~sin(C-A)+c~sin(A-B)=$
Question 2
Easy
Source :
HTET 2016
The origin on the curve $a^{2}x^{2}+b^{2}y^{2}=(x^{2}+y^{2})^{2}$ is a
Question 3
Easy
Source :
HTET 2016
The general solution of a differential equation of the type $\frac{dx}{dy}+P_{1}x=Q_{1}$ is
Question 4
Easy
Source :
HTET 2016
For all real values of x, the minimum value of $\frac{1-x+x^{2}}{1+x+x^{2}}$ is