Question
Easy

The value of $\sqrt{{91}+\sqrt{70+\sqrt121}}$ is-

1
9
2
10
3
11
4
12
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: Paper 2
Chapter: Power & Roots
Topic: Square Root & Cube Roots
Correct Answer
Option B
Explanation

To determine the value of \(\sqrt{91+\sqrt{70+\sqrt{121}}}\), we need to evaluate the expression step by step. 1. Evaluate the innermost square root: \[ \sqrt{121} = 11 \] 2. Substitute and evaluate the next square root: \[ \sqrt{70 + \sqrt{121}} = \sqrt{70 + 11} = \sqrt{81} \] \[ \sqrt{81} = 9 \] 3. Substitute and evaluate the outermost square root: \[ \sqrt{91 + \sqrt{70 + \sqrt{121}}} = \sqrt{91 + 9} = \sqrt{100}…Read More