Question
Easy

Vertices A, B, C of an isosceles triangle ABC are represented by complex numbers z1, z2, z3 respectively. If $\angle C=90^{\circ}$ then which of the following is correct?

1
$(z_{1}-z_{2})^{2}=2(z_{1}-z_{3})(z_{3}-z_{2})$
2
$(z_{1}-z_{2})^{2}=(z_{1}-z_{3})(z_{3}-z_{2})$
3
$z_{1}^{2}+z_{2}^{2}+z_{3}^{2}=z_{1}z_{2}z_{3}$
4
$z_{1}^{2}+z_{2}^{2}+z_{3}^{2}+z_{1}z_{2}z_{3}=0$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Algebra
Topic: Complex Numbers
Correct Answer
Option A
Explanation

To determine why Option 1 is the correct answer, we need to analyze the properties of an isosceles right triangle in the context of complex numbers. ### Explanation for Option 1: 1. Isosceles Right Triangle Properties: - In an isosceles right triangle, two sides are equal, and one angle is \(90^\circ\). - Given that \(\angle C = 90^\circ\), triangle ABC is an isosceles right triangle with \(\angle C\) as theтАжRead More

Vertices a b c - HTET Level 3 | Clear Cutoff