Which of the following letter is exactly in the middle of 3 and 1 in the given series ?
BE6DAU&3TIQ89C #2M
%U1MW75J8L

Question

Which of the following letter is exactly in the middle of 3 and 1 in the given series ?
 BE6DAU&3TIQ89C #2M
 %U1MW75J8L

Accepted Answer

To determine which letter is exactly in the middle of '3' and '1' in the given series, we need to first locate the positions of '3' and '1' in the series:

The series is: BE6DAU&3TIQ89C#2M%U1MW75J8L

1. Locate '3': 
   - '3' is the 8th character in the series.

2. Locate '1':
   - '1' is the 21st character in the series.

Now, we need to find the character that is exactly in the middle of these two positions. To do this, we calculate the middle position between 8 and 21:

- The middle position can be found by averaging the two positions: 
  $$
  \text{Middle position} = \frac{8 + 21}{2} = \frac{29}{2} = 14.5
  $$

Since we are dealing with discrete positions in a series, we round 14.5 to the nearest whole number, which is 15.

3. Identify the character at the 15th position:
   - The 15th character in the series is 'C'.

Therefore, the letter that is exactly in the middle of '3' and '1' is 'C'. This supports the given correct answer, which is Option 2.

Explanation for why other options are incorrect:

1. Option 1 (9):
   - '9' is the 13th character in the series, which is not the middle position between '3' and '1'.

3. Option 3 (#):
   - '#' is the 16th character in the series, which is not the middle position between '3' and '1'.

4. Option 4 (2):
   - '2' is the 17th character in the series, which is not the middle position between '3' and '1'.

Thus, Option 2 ('C') is the correct answer as it is the character exactly in the middle of '3' and '1' in the given series.