Question
Easy
Which of the following order of energies of molecular orbital of $N_{2}$ is correct?
1
$(\pi_{2p_{y}})<(\sigma_{2p_{z}})<({\pi^{*}}_{2p_{x}})\simeq({\pi^{*}}_{2p_{y}})$
2
$(\pi_{2p_{y}})>(\sigma_{2p_{z}})>({\pi^{*}}_{2p_{x}})\simeq({\pi^{*}}_{2p_{y}})$
3
$(\pi_{2p_{y}})<(\sigma_{2p_{z}})>({\pi^{*}}_{2p_{x}})\simeq({\pi^{*}}_{2p_{y}})$
4
$(\pi_{2p_{y}})>(\sigma_{2p_{z}})<({\pi^{*}}_{2p_{x}})\simeq({\pi^{*}}_{2p_{y}})$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Chemical Bonding and Thermodynamics
Topic: Chemical Bonding and Molecular Structure
Correct Answer
Option
Explanation
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