Question
Easy

Let
P = 12xy - 10y$^2$ – 18x$^2$,
Q = 14x$^2$ + 12y$^2$ + 9xy, and
R = 5y$^2$ - x$^2$ + xy
then (P + Q) – R =

1
22xy-3x$^2$ + 3y$^2$
2
22xy + 3x$^2$ - 3y$^2$
3
20xy-7x$^2$- 3y$^2$
4
20xy-3x$^2$- 3y$^2$
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: Paper 2
Chapter: Algebra
Topic: Algebraic Expressions
Correct Answer
Option D
Explanation

To solve the problem and verify why Option 4 is the correct answer, we need to perform the operations as specified in the question and compare the result with the given options. Step-by-Step Explanation: 1. Calculate P + Q: Given: - \( P = 12xy - 10y^2 - 18x^2 \) - \( Q = 14x^2 + 12y^2 + 9xy \) Add P and Q: \[ P + Q = (12xy…Read More

Let p q r then p plus q minus r algebrai - CTET Paper 2 | Clear Cutoff